2x^4-4x^2+3=0

Solution for 2x^4-4x^2+3=0 equation:

Simplifying
2x4 + -4x2 + 3 = 0

Reorder the terms:
3 + -4x2 + 2x4 = 0

Solving
3 + -4x2 + 2x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
1.5 + -2x2 + x4 = 0

Move the constant term to the right:

Add '-1.5' to each side of the equation.
1.5 + -2x2 + -1.5 + x4 = 0 + -1.5

Reorder the terms:
1.5 + -1.5 + -2x2 + x4 = 0 + -1.5

Combine like terms: 1.5 + -1.5 = 0.0
0.0 + -2x2 + x4 = 0 + -1.5
-2x2 + x4 = 0 + -1.5

Combine like terms: 0 + -1.5 = -1.5
-2x2 + x4 = -1.5

The x term is -2x2.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x2 + 1 + x4 = -1.5 + 1

Reorder the terms:
1 + -2x2 + x4 = -1.5 + 1

Combine like terms: -1.5 + 1 = -0.5
1 + -2x2 + x4 = -0.5

Factor a perfect square on the left side:
(x2 + -1)(x2 + -1) = -0.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.